20/05/2024
400W DC-DC Boost Power Supply Module 8.5V-50V to 10V-60V 15A Adjustable Step UP CC Voltage Converter
Descriptions:
It is a 400W DC-DC boost power module.It is a CVCC power supply.It can convert DC 8.5V-50V to DC 10V-60V.
2>.Feature:
1.It supports 400W high power.
2.Its conversion efficiency is high,up to 96%.
3.It has overcurrent protection.
4.It has a voltage regulator and a current regulator.
5.It is widely used.
3>.Parameter:
1.Product Name:400W DC-DC Boost Power Module
2.Input Voltage:DC 8.5V~50V
3.Input Current:15A(Max),more than 8A,please strengthen heat dissipation.
4.Static Working Current:10mA
5.Output Voltage:12A(Max),more than 8A,please strengthen heat dissipation.
6.Constant Current Range:0.2A~12A
7.Output Power:Input Voltage*10A
8.Working Frequency:150KHz
9.Conversion Efficiency:96%(Max)
10.Work Temperature:-40℃~85℃
11.Work Humidity:5%~95%RH
12.Size:67*50*38mm
4>.Output Voltage/Current Adjustment Method:
1.Adjust the "CV-ADJ" potentiometer,according to your battery or LED,set the output voltage to the voltage value you need.For example,the voltage of 10 LED strings is adjusted to 37V.Turn up the voltage counterclockwise and turn down the voltage clockwise.
2.Adjust the "CC-ADJ" potentiometer counterclockwise for about 30 turns,set the output current to the minimum,connect the LED,and adjust the CC-ADJ potentiometer to the current you need.For battery charging,after the battery is discharged,connect to the output and adjust RV2 to the current you need.(When used for charging,you must use the discharged battery to adjust it,because the battery has more power.More,the lower the charging current.) The counterclockwise current decreases,and the clockwise current increases.
5>.Application:
1.DIY a regulated power supply,input 12V,output can be adjusted from 12-50V.